a-robots-conundrum/robotgame/logic/colourboxes.py

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2012-08-08 14:10:10 +02:00
#!/usr/bin/env python
# -*- coding: utf-8 -*-
# This file is part of ROBOTGAME
#
# ROBOTGAME is free software: you can redistribute it and/or modify it under the
# terms of the GNU General Public License as published by the Free Software
# Foundation, either version 3 of the License, or (at your option) any later
# version.
#
# ROBOTGAME is distributed in the hope that it will be useful, but WITHOUT ANY
# WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR
# A PARTICULAR PURPOSE. See the GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License along with
# ROBOTGAME. If not, see <http://www.gnu.org/licenses/>.
#
# ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' '
#
# colourboxes.py
# --------------------
# date created : Wed Aug 8 2012
# copyright : (C) 2012 Niels G. W. Serup
# maintained by : Niels G. W. Serup <ns@metanohi.name>
import random
def generate_colour_boxes(nwells, nboxes):
"""
Generate colour boxes that can be used to make all wells white.
Arguments:
nwells -- number of wells
nboxes -- maximum number of boxes needed to make all wells white.
Return [[(r, g, b)]]
where r : 0|1, g : 0|1, b : 0|1
"""
nbits = nwells * 3
data = [[0 for _ in range(nboxes)] for _ in range(nbits)]
def insert_1():
t = random.randrange(0, nboxes)
for y in range(t, nboxes) + range(0, t):
if data[x][y] == 0:
data[x][y] = 1
break
for x in range(len(data)):
insert_1()
for _ in range(random.randrange(0, (nboxes + 1) / 2)):
insert_1()
insert_1()
boxes = []
for y in range(nboxes):
box = []
boxes.append(box)
for x in range(0, nbits, 3):
r = data[x][y]
g = data[x + 1][y]
b = data[x + 2][y]
box.append((r, g, b))
return boxes
def generate_random_box(nwells):
r = lambda: random.choice((0, 1))
return [(r(), r(), r()) for _ in range(nwells)]
def makes_all_wells_white(boxes):
"""
Determine if the boxes make all wells white when XOR'ed together.
"""
total = 0
for box in boxes:
n = 0
for r, g, b in box:
n <<= 1
n |= r
n <<= 1
n |= g
n <<= 1
n |= b
total ^= n
return total == 2**(len(boxes[0]) * 3) - 1